Question

दो लगातार सम संख्याओं का जोड़ 422 है, तो संख्याएँ बताइए।​

Answer 1

Answer:

Let's 1st no. = x

Let's 2nd no. = x+2

According to Question :

$x + x + 2 = 422 \\ \\ 2x = 422 - 2 \\ \\ x = \frac{420}{2} \\ \\ x = 210$

$\large \boxed{ \bf1st \: Number = 210} \\ \\ \large \boxed{ \bf2nd \: Number = 212}$

Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$.

• दो लगातार सम संख्याओं का जोड़ 422 है, तो संख्याएँ बताइए।

____________________

$\large{\underline{\underline{\mathfrak{\sf{SOLUTION:-}}}}}$.

$\large{\underline{\underline{\mathfrak{\sf{Given\:Here:-}}}}}$.

• Sum of two alter even positive number = 422

__ __________________

$\large{\underline{\underline{\mathfrak{\sf{FIND\:HERE:-}}}}}$.

• Value of alter even number

___________________

$\large{\underline{\underline{\mathfrak{\sf{Explanation:-}}}}}$.

Let,

• x and x+2 is a alter even positive number

So,

A/C to question

$\implies\:(x+x+2)\:=\:422$

$\implies\:(2x)\:=\:422-2$

$\implies\:x\:=\frac{420}{2}$

$\implies\boxed{\boxed{\:x\:=\:210}}$

And,

$\large\boxed{\boxed{\:(x+2)\:=\:210+2\:=\:212}}$

____________________

$\large{\underline{\underline{\mathfrak{\sf{Answer:-}}}}}$.

• First even number X = 210

• Second even number (x+2) = 212

___________________

$\large{\underline{\underline{\mathfrak{\sf{Answer\:Checkup:-}}}}}$.

• Sum of two even number = 422

So,

$\implies\:(x+x+2)\:=\:422$

Keep value of x and (x+2)

$\implies\:(210+212)\:=\:422$

$\implies\:422\:=\:422$

L.H.S = R.H.S

That't proved

______ ____________