द्रव्यमान की विमा M लंबाई की विमा L और समय की विमा T व विद्युत धारा की विमा I के पदों में किसी विधुत परिपथ में प्रतिरोध की विमा होगी
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Answer:
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[{2/3 cosec^2 (58)} - {2/3 (cot 58)( tan 32)} - {5/3 (tan 13)( tan 37 )( tan 45 )( tan 53 )( tan 77)}]
Using: tan x = cot (90 - x)
={[2/3 cosec^2 58} -{2/3 cot^2 58} - {5/3 (tan 13 tan 37 tan 45 cot 37 cot 13}]
=2/3(cosec^2 58 - cot^2 58) - 5/3 [since, tan 45 = 1]
=2/3 -5/3 [Using cosec^2 x - cot^2 x = 1]
= -1
Read more on Brainly.in - https://brainly.in/question/3005232#readmore⏬ Hello Friend Here Is Your Answer ⏬
[{2/3 cosec^2 (58)} - {2/3 (cot 58)( tan 32)} - {5/3 (tan 13)( tan 37 )( tan 45 )( tan 53 )( tan 77)}]
Using: tan x = cot (90 - x)
={[2/3 cosec^2 58} -{2/3 cot^2 58} - {5/3 (tan 13 tan 37 tan 45 cot 37 cot 13}]
=2/3(cosec^2 58 - cot^2 58) - 5/3 [since, tan 45 = 1]
=2/3 -5/3 [Using cosec^2 x - cot^2 x = 1]
= -1
Read more on Brainly.in - https://brainly.in/question/3005232#readmore⏬ Hello Friend Here Is Your Answer ⏬
[{2/3 cosec^2 (58)} - {2/3 (cot 58)( tan 32)} - {5/3 (tan 13)( tan 37 )( tan 45 )( tan 53 )( tan 77)}]
Using: tan x = cot (90 - x)
={[2/3 cosec^2 58} -{2/3 cot^2 58} - {5/3 (tan 13 tan 37 tan 45 cot 37 cot 13}]
=2/3(cosec^2 58 - cot^2 58) - 5/3 [since, tan 45 = 1]
=2/3 -5/3 [Using cosec^2 x - cot^2 x = 1]
= -1
Read more on Brainly.in - https://brainly.in/question/3005232#readmore⏬ Hello Friend Here Is Your Answer ⏬
[{2/3 cosec^2 (58)} - {2/3 (cot 58)( tan 32)} - {5/3 (tan 13)( tan 37 )( tan 45 )( tan 53 )( tan 77)}]
Using: tan x = cot (90 - x)
={[2/3 cosec^2 58} -{2/3 cot^2 58} - {5/3 (tan 13 tan 37 tan 45 cot 37 cot 13}]
=2/3(cosec^2 58 - cot^2 58) - 5/3 [since, tan 45 = 1]
=2/3 -5/3 [Using cosec^2 x - cot^2 x = 1]
= -1
Read more on Brainly.in - https://brainly.in/question/3005232#readmore⏬ Hello Friend Here Is Your Answer ⏬
[{2/3 cosec^2 (58)} - {2/3 (cot 58)( tan 32)} - {5/3 (tan 13)( tan 37 )( tan 45 )( tan 53 )( tan 77)}]
Using: tan x = cot (90 - x)
={[2/3 cosec^2 58} -{2/3 cot^2 58} - {5/3 (tan 13 tan 37 tan 45 cot 37 cot 13}]
=2/3(cosec^2 58 - cot^2 58) - 5/3 [since, tan 45 = 1]
=2/3 -5/3 [Using cosec^2 x - cot^2 x = 1]
= -1
Read more on Brainly.in - https://brainly.in/question/3005232#readmore⏬ Hello Friend Here Is Your Answer ⏬
[{2/3 cosec^2 (58)} - {2/3 (cot 58)( tan 32)} - {5/3 (tan 13)( tan 37 )( tan 45 )( tan 53 )( tan 77)}]
Using: tan x = cot (90 - x)
={[2/3 cosec^2 58} -{2/3 cot^2 58} - {5/3 (tan 13 tan 37 tan 45 cot 37 cot 13}]
=2/3(cosec^2 58 - cot^2 58) - 5/3 [since, tan 45 = 1]
=2/3 -5/3 [Using cosec^2 x - cot^2 x = 1]
= -1
Read more on Brainly.in - https://brainly.in/question/3005232#readmore
Explanation: