Question

Tha roots of the quadrantic education 4 x - 81 = 0 are

Answer 1

Answer:

4x-81

= >x=81/4

here simply solve the equation

Answer 2

$\huge \bigstar\fbox \colorbox{magenta}{Answer} \bigstar$

${4x}^{2} - 81 = 0 \\ { \tt{using \: {x}^{2} - {y}^{2} = (x + y)(x - y)}} \\ {(2x)}^{2} - {(9)}^{2} = 0 \\ (2x + 9)(2x - 9)$

${ \tt{either \: 2x + 9 = 0}} \\{ \tt {2x = - 9 }}\\ { \tt{x = \frac{ - 9}{2} }}$

$\red{ \tt{or \: 2x - 9 = 0}} \\ \red{ \tt{2x = 9}} \\ \red{ \tt{x = \frac{9}{2} }}$

$\pink{ \sf{hence \: x = + \frac{9}{2} \: or \: \frac{ - 9}{2} }}$