tha salary of gaurav in first year is rs.600 per month. he gets an increment of 20per month find his total earning during 6year sirvice.
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first year salary (a) = rs 600
every month increment of rs 20 i.e difference (d)
no.of year =6
there are 12month in 1 year
therefore there are 72month in 6year
we know that
Sn = n÷2[2a+(n-1)×d]
S72 =72÷2[2(600)+(72-1)×20]
=36[1200+1420]
=36×2620
=94320
therefore gaurav total earning during six year is rs 94320
every month increment of rs 20 i.e difference (d)
no.of year =6
there are 12month in 1 year
therefore there are 72month in 6year
we know that
Sn = n÷2[2a+(n-1)×d]
S72 =72÷2[2(600)+(72-1)×20]
=36[1200+1420]
=36×2620
=94320
therefore gaurav total earning during six year is rs 94320
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