दौड़ के एक ट्रैक का बायाँ और दायाँ सिरा अर्धवृत्ताकार है। भीतरी समांतर रेखाखंडों के बीच की
दूरी 60 मी है और प्रत्येक 106 मी लंबा है। यदि ट्रैक 10 मी चौड़ा हो तो ट्रैक का क्षेत्रफल ज्ञात करें।
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Answer:
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Step-by-step explanation:
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Answered by
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Answer:
4320 m^2 ...GQ
Step-by-step explanation:
area of internal rectangular portion
= 106×60= 6360 m^2
radii of each internal semicircle
=60/2= 30m
circumference of 2 internal semi circle
= 2 × 22/7 × 30 = 1320/7m
1 round of internal line of track
= (1320/7) + (106+106) = 2804/7m
area of external rect fig =(60+10+10) × 106 =8480m^2
rect. shaded track area = 8480-6360 =2120m^2
radii of each external semicircl=80/2=40
area of both shaded semicircular portions of the track = π(R^2-r^2)
= 22/7(40^2-30^2) = 2200m^2
total area of the track =2120+2200
= 4320m^2
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