Math, asked by mukeshstm6881, 8 months ago

दौड़ के एक ट्रैक का बायाँ और दायाँ सिरा अर्धवृत्ताकार है। भीतरी समांतर रेखाखंडों के बीच की
दूरी 60 मी है और प्रत्येक 106 मी लंबा है। यदि ट्रैक 10 मी चौड़ा हो तो ट्रैक का क्षेत्रफल ज्ञात करें।​

Answers

Answered by vijay9283
0

Answer:

sgczgbfucfhgehvdhv

Step-by-step explanation:

cg5,='66'66.=5

Answered by TheLostMonk
0

Answer:

4320 m^2 ...GQ

Step-by-step explanation:

area of internal rectangular portion

= 106×60= 6360 m^2

radii of each internal semicircle

=60/2= 30m

circumference of 2 internal semi circle

= 2 × 22/7 × 30 = 1320/7m

1 round of internal line of track

= (1320/7) + (106+106) = 2804/7m

area of external rect fig =(60+10+10) × 106 =8480m^2

rect. shaded track area = 8480-6360 =2120m^2

radii of each external semicircl=80/2=40

area of both shaded semicircular portions of the track = π(R^2-r^2)

= 22/7(40^2-30^2) = 2200m^2

total area of the track =2120+2200

= 4320m^2

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