Question

द्विघात समीकरण 2x2-7x+3 = 0 के मूल ज्ञात कीजिए।
Find the roots of quadratic equation 2x2-7x+3 = 0.​

Answer 1

⟹ 2x²-7x+3=0

⟹ x=-b+_√b²-4ac/2a

⟹ x=7+_√49-24/4

⟹ x=7+_√25/4

⟹ x=7+_5/4

⟹ x=1/2,3

Answer 2

2x2 – 7x + 3 = 0 ⇒ 2x2 – 7x = – 3

Dividing by 2 on both sides, we get

⇒ x2 -7x/2 = -3/2

⇒ x2 -2 × x ×7/4 = -3/2

On adding (7/4)2 to both sides of equation, we get

⇒ (x)2-2×x×7/4 +(7/4)2 = (7/4)2-3/2

⇒ (x-7/4)2 = (49/16) – (3/2)

⇒(x-7/4)2 = 25/16  

⇒(x-7/4)2 = ±5/4

⇒ x = 7/4 ± 5/4

⇒ x = 7/4 + 5/4 or x = 7/4 – 5/4

⇒ x = 12/4 or x = 2/4

⇒ x = 3 or x = 1/2