Question

द्विघात समीकरण (i) 2x^-5x+3=0
(ii) ax -2abx = 0 के मूल निकाले​

Answer 1

Step-by-step explanation:

1. $2{x}^{2} - 5x + 3 = 0 \\ 2 {x}^{2} - 2x - 3 x + 3 = 0 \\ 2x(x - 1) - 3(x - 1) = 0 \\ (2x - 3)(x - 1) = 0 \\ x = 1 \: \: \: \: \: x = \frac{3}{2}$
2. $ax - 2abx = 0 \\ x = 0$

Answer 2

Answer:

Take the answer and write it