द्विघात समीकरण ज्ञात कीजिए जिसके मूल 3 व -8 है
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Answer:
x^2+5x-24=0
Step-by-step explanation:
ax^2+bx+c=0
=>
x^2 + (b/a)x + (c/a) =0 ...................(1)
मूलो का योग = -b/a = 3+(-8)= -5
=>b/a = 5 .............(2)
मूलो का गुणनखण्ड = c/a = 3(-8)= -24
=> c/a = -24 ..........(3)
by eqn (1) (2) & (3) =>
x^2+5x-24=0
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