Question

द्विघात समीकरण x² - 8x + 12 = 0 के हल गुणनखण्ड विधि से ज्ञात कीजिये।​

Answer 1

Answer:

x=2, x=6

Explanation:

$x^{2} -8x+12=0\\x^{2} -2x-6x+12=0\\(x^{2}-2x) -(6x+12)=0\\x(x-2)-6(x-2) =0\\(x-6) (x-2)=0\\x=6,,, x= 2$

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Answer 2

Explanation:

$}^$

$x ^{2} - 8x + 12 \\ {x }^{2} - (6 + 2)x + 12 \\ {x}^{2} - 6x - 2x + 12 \\ x(x - 6) - 2(x - 6) \\ (x - 2)(x - 6) \\ x =6 \\ x = 2$