Math, asked by prachana2264, 4 months ago

द्विघात व्यंजक
x2 + 7x + 10
के शून्यक ज्ञात कीजिए​

Answers

Answered by harshitha926594
1

Answer:

\color{red}\huge\bold\star\underline\mathcal{Solution\: :-}\star \\  \\ {x}^{2}  + 7x + 10 = 0 \\  {x}^{2}  + 5x + 2x + 10 = 0 \\ x(x + 5) + 2(x + 5) = 0 \\ (x + 5)(x + 2) = 0 \\ x + 5 = 0 \: \:  or \:  \: x + 2 = 0 \\ x =  - 5 \:  \:  \: or \:  \:  \: x =  - 2

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