Question

द्विघातीय समीकरण (x2-4x-12 = 0) को हल करो।​

Answer 1

Step-by-step explanation:

$x {}^{2} - 4x - 12 = 0 \\ x {}^{2} - 6x + 2x - 12 = 0 \\ x(x - 6) + 2(x - 6) = 0 \\( x - 6)(x + 2) = 0 \\ hence \\ x = 6 \: , - 2$

i hope it will be helpful

Answer 2

Answer:

x = -2 or x = 6

Step-by-step explanation:

x² - 4x - 12 = 0

x² - 6x + 2x - 12 = 0

x(x - 6) +2(x - 6) = 0

(x + 2)(x - 6) = 0

(x + 2) = 0 or (x - 6) = 0

=> x = -2 or x = 6