thal AB = CD
9. In AABC, A = 60", B = 40". Which side of this triangle is the smallest ? Give reason
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Answered by
1
Answer:
By angle sum property of a triangle,we know that sum of all the angles is 180*.
So,
angle A+ angle B+ angle C = 180*
=60*+40*+angle C = 180*
=100*+angle C =180*
angle C =80*
Thus, angle B is the smallest.
Since, the side opposite to smaller angle is smaller, angle B is the smallest side.
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Answered by
2
Answer:
Explanation:
Here, ∠B=40∘and∠A=60∘.
∴ ∠C=180∘−(40∘+60∘)=80∘.
Thus, ∠C is largest and ∠B is smallest.
So, the side opposite to ∠C is longest.
Hence, the longest side is a A.
Also, the side opposite to ∠B is shortest.
∴ BC is the shortest side.
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