Question

Than find value of X.​

Answer 1

Answer:

x = 1

Step-by-step explanation:

${x}^{2} + \frac{1}{ {x}^{2} } + x + \frac{1}{x} - 4 = 0 \\ \frac{ {x}^{4} + 1 + {x}^{3} + x - 4 {x}^{2} }{ {x}^{2} } = 0\\ \frac{ {x}^{4} + {x}^{3} - 4 {x}^{2} + x + 1}{ {x}^{2} } = 0 \\ {x}^{4} + {x}^{3} - 4 {x}^{2} + x + 1 = 0 \\ \\ x = 1$

Answer 2

Answer:

answer is 1 ok ............