Question

Thandiwe is 20 years older than her daughter Jelita. 10 years ago, Thandiwe was twice as old as Jelita. Find:
a) Thandiwe's age       
b) Jelita's age         

Answer 1

Step-by-step explanation:

Let,

the age of Jelita-x

age of Thandiwe : 20+x

Before 10 years

Age of Thandiwe : 2x

current age of Thandiwe =2x-10=x-10

. x=20

a) 40years

b) 20years

3x+20=20+2x

Answer 2

Solution :

Let age of Jelita be ' x ' years

So, age of Thandiwe will be ' x + 20 '

Ten years ago

• Jelita = x - 10

• Thandiwe = x + 20 - 10

Now,

According to Question :

( x + 20 ) - 10 = 2 ( x - 10 )

⇒ x + 10 = 2x - 20

⇒ x - 2x = - 20 - 10

⇒ - x = - 30

∴ x = 30

Age of Jelita is 30 years.

Now,

Age of Thandiwe :

• x + 20 = 30 + 20 = 50 years

Answer : Jelita is 30 years old and Thandiwe is 50 years old.

$\rule{200}2$