Question

thank her answers
$\huge\mathbb\fcolorbox{purple}{lavenderblush}{✰Question}$


The sides of a triangle are of lenghts 15cm,36cm and 39cm.find the lenght of perpendicular from the opposite vertex to the side of lenght 39cm​

Answer 1

Answer:

$<marquee behaviour-move><font color="blue black"><h2>here is ur answer </ ht></marquee>$

here, a=15,b=36, c=39. Area= 270. And, as it is from the opposite vertex of side of the length 39; Base is 39

.✦$\red{\bf{@XxItZCrAZyGiRLxX1}}$࿐

Answer 2

Answer:

$\huge\mathcal{\fcolorbox{aqua}{azure}{\red{✿Yøur-Answer♡❖}}}$

$⟹ \large\bf{\underline{\red{VERIFIED✔}}}$

We know that s=(a+b+c)/2

here, a=15,b=36, c=39.

Therefore: s= (15+36+39)/2

s=45

And Area

$= \sqrt{s(s-a)(s-b)(s-c)}s(s−a)(s−b)(s−c)$

Therefore: area

$= \sqrt{45(45-15)(45-36)(45-39)}45(45−15)(45−36)(45−39)$

According to the formula: area=(height × base)/2

Filling the information we have,

270 = (H * 39)/2

Therefore: H = 13.84

$\bf\colorbox{lavender}{{\color{b}{✿Hope It Helps You ♡❖ }}}$

${\sf{\mathcal{\red{@ᴄᴜᴛᴇʙᴜɴɴʏ21࿐}}}}$