Question

thank my answers
follow me
If x+y+z =9 and xy + yz + zx =26 then find x^3 + y^3 z^3 - 3xyz.
​

Answer 1

Answer:

hopefully it's helpful for u mark me as brainliest and follow me

Step-by-step explanation:

(x3 + y3 + z3 - 3xyz)

= (x + y + z) (x2 + y2 + z2 - xy - yz - zx)

= (x + y + z) [(x + y + z)2 - 3(xy + yz + zx)]

= 9 x (81 - 3 x 23)

= (9 x 12)

= 108

Answer 2

Answer:

27

Justification:

-> (x3 + y3 + z3 - 3xyz)

= (x + y + z) (x2 + y2 + z2 - xy - yz - zx)

= (x + y + z) [(x + y + z)2 - 3(xy + yz + zx)]

= 9 x (81 - 3 x 26)

= (9 x 3)

= 27

All the best ☺️