Math, asked by BrainlyShadow01, 9 months ago

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If x+y+z =9 and xy + yz + zx =26 then find x^3 + y^3 z^3 - 3xyz.

Answers

Answered by suneetad45
2

Answer:

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Step-by-step explanation:

(x3 + y3 + z3 - 3xyz)

= (x + y + z) (x2 + y2 + z2 - xy - yz - zx)

= (x + y + z) [(x + y + z)2 - 3(xy + yz + zx)]

= 9 x (81 - 3 x 23)

= (9 x 12)

= 108

Answered by Anonymous
31

Answer:

27

Justification:

-> (x3 + y3 + z3 - 3xyz)

= (x + y + z) (x2 + y2 + z2 - xy - yz - zx)

= (x + y + z) [(x + y + z)2 - 3(xy + yz + zx)]

= 9 x (81 - 3 x 26)

= (9 x 3)

= 27

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