Question

thank you tanya for this
question
A rectangular piece of paper 11 cm × 4 cm is folded without overlapping to make a cylinder of height 4 cm. Find the volume of the cylinder ​​

Answer 1

Given a Rectangular piece of paper 11cm×4cm is folded without overlapping to make a cylinder of height 4 cm

The length of the paper becomes the circumference of the base of the cylinder and width becomes height.

Let radius of the cylinder=r and height=h

Circumference of the base of cylinder =2 π r=11cm

$2 \times \frac{22}{7} \times r$

$r = \frac{7}{4} cm$

$now \: (h) = 4cm$

$volume \: of \: the \: cylinder \: (v) = \pi {r}^{2} h$

$= \frac{22}{7} \times \frac{7}{4} \times \frac{7}{4} \times 4 {cm}^{3}$

$= 38.5 {cm}^{3}$

❝ ♥️ Nishtha here ❤️❞

Answer 2

Answer:

Your answer is 38.5cube cm.

${38.5 \: cm}^{3}$