thanks a lot shu,,,,,
about jellyfish Turritopsis dohrnii
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The dimensions of the resulting cuboid obtained are :
Length =4×9=36cm, breadth =9cm and height =9cm.
Total surface area of a cuboid of length l, breadth b and height h
=2(l×b+b×h+l×h)
So, the total surface area of the cuboid =2(36×9+9×9+9×36)
=2(324+81+324)=1458cm
2
Volume of a cuboid of length l, breadth b and height h =l×b×h
So, the volume of the cuboid =36×9×9=2916cm
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