Question

Thanks for answering (if you did)..

Answer 1

opt. 2 is right ans...if helped then mark as brainliest please

Answer 2

Initially when the block is moving with constant speed
F_net = 0
mgSinx = μmgCosx ……[Here I took x instead of θ] ——(1)

When the block is given horizontal acceleration it moves upwards with constant speed. The component of this force along wedge is maCosx
F_net = 0
maCosx = mgSinx + μmgCosx
maCosx = 2mgSinx ……[∵ from (1)]
a = 2gTanx

Acceleration of wedge is 2gTanx