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opt. 2 is right ans...if helped then mark as brainliest please
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Initially when the block is moving with constant speed
F_net = 0
mgSinx = μmgCosx ……[Here I took x instead of θ] ——(1)
When the block is given horizontal acceleration it moves upwards with constant speed. The component of this force along wedge is maCosx
F_net = 0
maCosx = mgSinx + μmgCosx
maCosx = 2mgSinx ……[∵ from (1)]
a = 2gTanx
Acceleration of wedge is 2gTanx
F_net = 0
mgSinx = μmgCosx ……[Here I took x instead of θ] ——(1)
When the block is given horizontal acceleration it moves upwards with constant speed. The component of this force along wedge is maCosx
F_net = 0
maCosx = mgSinx + μmgCosx
maCosx = 2mgSinx ……[∵ from (1)]
a = 2gTanx
Acceleration of wedge is 2gTanx
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