Question

thanks in advance for the answer

Answer 1

hey mate
here's the solution

Answer 2

Here is your solution

Let,
r and R are the radii of the base of two cylindrical jars.

Let h and H are the heights of the two cylindrical jars.

Now, 

Diameter of the first jar/Diameter of the second jar = 3/4

=> 2πr/2πR = 3/4

=> r/R= 3/4

Again, 

 Volume of the first jar/Volume of the second jar = 1 (since same amount of the milk contain)

=> πr^2 h/πR^2 H = 1

=> r^2 h/R^2 H = 1

=> (r^2 /R^2 )×(h/H) = 1

=> (3/4)^2 × (h/H) = 1

=> (9/16) × (h/H) = 1

=> h/H = 1/(9/16)

=> h/H = 16/9

=> H/h = 9/16

=> H : h = 9 : 16

HENCE,

So, the ratio of their heights is 9 : 16

Hope it helps you