Math, asked by ak9905817278, 4 months ago

thanks my answer friend and follow me and get it back...ok.... Given :

Angles of a quadraliteral are (p + 25)°, 2p°, (2p - 15)° and (p + 20)°

To Find :

The value of largest angle

Solution :

The sum of all four interior angles of a quadraliteral is 360°.

\begin{gathered} \\ : \implies \sf \: (p+25) {}^{ \circ} + 2p {}^{ \circ} + (2p - 15) {}^{ \circ} + (p+20) {}^{ \circ} = {360}^{ \circ} \\ \\ \end{gathered}:⟹(p+25)∘+2p∘+(2p−15)∘+(p+20)∘=360∘​

\begin{gathered} \\ : \implies \sf \: 6p + 30 = {360}^{ \circ} \\ \\ \end{gathered}:⟹6p+30=360∘​

\begin{gathered} \\ : \implies \sf \: 6p = 360 - 30 \\ \\ \end{gathered}:⟹6p=360−30​

\begin{gathered} \\ : \implies \sf \: 6p = 330 \\ \\ \end{gathered}:⟹6p=330​

\begin{gathered} \\ : \implies \sf \: p = \dfrac{330}{6} \\ \\ \end{gathered}:⟹p=6330​​

\begin{gathered} \\ : \implies{\underline{\boxed{\pink{\mathfrak{p = 55}}}}} \: \bigstar \\ \\ \end{gathered}:⟹p=55​​★​

Then the values of angles are ,

(p + 25)° = 55 + 25 = 80°

2p° = 55(2) = 110°

(2p - 15)° = 2(55) - 15 = 110 - 15 = 95°

(p + 20)° = 55 + 20 = 75°

Among the given angles of quadrilateral , 110° is largest angle.

Hence ,

The value of largest angle among the given angles of quadrilateral is 110°. So , Option(b) is the required answer

Answers

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