Question

दर्शाइए कि कोई भी धनात्मक विषम पूर्णांक 6q + 1, 6q + 3 या 6q + 5 के रूप का होता
है, जहाँ q कोई पूर्णांक है।
Show that any positive odd integer is of the form 6q + 1, 6q + 3 or 6q + 5,
where q is some integer.​

Answer 1

Answer:

Koi real number

Step-by-step explanation:

6q+1=

q=1

6×1+5=11

Answer 2

Any positive odd integer is of the form 6q+1,6q+3 or 6q+5.

Let 'a' be a given integer. Let 'q' be the quotient and 'r' be the remainder.

.) Now , on dividing an integer 'a' by 6 , we get ,

a = 6q + r

Where values of r can be ,

r = 0,1,2,3,4,5

Now we will take different cases

.) Case - 1 , when r=0

a = 6q, even no

.) Case -2 , when r=1

a = 6q + 1, odd no

.) Case -3 , when r=2

a = 6q + 2, even no

.) Case -4 , when r = 3

a=6q + 3,odd no

.) Case -5 , when r=4

a=6q + 4,even no

.) Case -6 , when r=5,

a= 6q + 5 , odd no