Question

that 3 is a zero of the polynomial x cube minus 8 x square + 8 x + 21​

Answer 1

Answer:

x=3

therefore , P(x) = x3-8x2+8x+21

P(3) = (3) 3-8(3) 2+8(3) +21

= 27-72+24+21

= 72-72

= 0

as it is zero therefore, it is the zero is the zero of the polynomial.

* HOPE IT HELPS YOU*

Answer 2

yes , 3 is the zero of the polynomial x³ -8x² +8x +21

Step-by-step explanation:

given polynomial = x³ -8x² +8x +21

we have to show that 3 is the zero of this polynomial

then

p(x) = x³ -8x² +8x +21

putting the value of x= 3

we get

x³ -8x² +8x +21

= (3)³ - 8(3)² + 8(3) +21

= 27 -72+24+21

= -45 +24+21

= -21 +21

= 0

hence ,

3 is the zero of the polynomial x³ -8x² +8x +21

#Learn more:

If α and β are the zeroes of the poly. 4x²+4x+1 then form a quadratic poly. whose zeroes are 2α and 2β

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