Question

that 6 + 3 root 2 is an irrational number​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Let us assume 6+3√2 is a

ratoinal number .

6+3√2 = a/b , where

a,b are integers , b≠0.

=> 3√2 = a/b - 6

=> 3√2 = ( a - 6b )/b

=> √2 = ( a - 6b )/3b

Since a,b are integers ,

(a - 6b)/3b is rational, and so

√2 is rational .

This contradicts the fact that

√2 is irrational.

Hence , 6 + 3√2 is irrational.

•••••