that angle of elevation of the top of a tower from a point on the ground which is 30m away from the foot of the tower,is 30°.find the height of the tower with figure
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1
Answer:10√3
Step-by-step explanation:
tan 30=1/√3
AB/30=1/√3
AB=30/√3=10√3m
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Answered by
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Answer: Please mark it as brainliest
10✓3 m
Step-by-step explanation:
tan 30° = AB/BC
1/✓3 = h/30
30 = h✓3
30/✓3 = h
by rationalizing
30✓3/3 = h
10✓3= h
So, the height is 10✓3 m
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