That angle triangle ABC with AB is equal to 4 cm BC is equal to 3.5 cm and AC is equal to 4 cm what type of triangle is this
Answers
Step-by-step explanation:
assertion.
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ANSWER
Steps:
1. draw base AB=4cm
2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc.
3. let C be the point of intersection of the above 2 lines.
4. draw a ray AX making an acute angle with line AB on the opposite side if the vertex C.
5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1
6. join A3B and draw a parallel line B
′
A2
7. draw a line parallel to BC to intersect AC at C
′
Thus AB
′
C
′
is a required triangle.
Justification;
By construction,
AB
AB
′
=
AA3
AA2
=
3
2
also B
′
C
′
∥BC
∴∠AB
′
C
′
=∠ABC
In △AB
′
C
′
,△ABC
∠A=∠A
∠AB
′
C
′
=∠ABC
△AB
′
C
′
∼△ABC
⇒
AB
AB
′
=
AC
AC
′
=
BC
B
′
C
′
∴
AB
AB
′
=
AC
AC
′
=
BC
B
′
C
′
=
3
2
solution
Answer:
Isoceles Triangle
Step-by-step explanation:
Isoceles Triangle has 2 sides equal. The equal sides are the base angles of the triangle.
AC= 4cm
AB= 4cm
BC= 3.5cm
AC=AB (Shows that 2 sides are equal)
Therefore, the triangle formed by the given measurement is an isoceles triangle
Hope it helps...