that CF and LCM of two numbers are 9 and 270 respectively if one of the numbers is 45 find the other number
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hey!!! here is your answer
hcf=9; lcm=270; one number= 45; other number= y(say)
product of two numbers= their (hcf x lcm)
45y=270x9
45y=2430
y=2430÷45=54
hence
other number= 54
hope it will help you
hcf=9; lcm=270; one number= 45; other number= y(say)
product of two numbers= their (hcf x lcm)
45y=270x9
45y=2430
y=2430÷45=54
hence
other number= 54
hope it will help you
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