That internal dimensions of rectangular hall is 15m*12m*4m there r 4 windows with 2m*1.5m and 2 doors with dimensions 1.5m*2.5m find cost of white washing of 4 walls and ceiling if cost of white washing per meter square is ₹5
Answers
Answer:
The cost of white washing of 4 walls and ceiling will be Rs 1882.5
Step-by-step explanation:
Surface area of 4 walls = 2(LH + BH)
= 2(15*4 + 12*4)
= 2(60 + 48)
= 216 m²
surface area of ceiling = L x B
= 15 x 12
= 180 m²
surface area of 4 windows = 4 x 2 x 1.5
= 12 m²
surface area of 2 doors = 2 x 1.5 x 2.5
= 7.5 m²
Hence total surface area to be white washed
= 216 + 180 - 12 - 7.5
= 376.5 m²
Cost of white washing per m² = Rs 5
=> Cost of white washing 376.5 m² = 376.5 x 5
= 1882.5 Rs
Hence the cost of white washing of 4 walls and ceiling will be Rs 1882.5
Answer:
1882.5
Step-by-step explanation:
surface area of 4 walls= 2(LH + BH)
=2(15*4+12*4)
=2(60+48)
=216m^2
surface area of ceiling=L*B
=15*12
=180m^2
area of 4 windows= 4*2*1.5
=12m^2
area of 2 doors= 2*1.5*2.5
=7.5m^2
total surface area to be white washed= 216+80-12-7.5
=376.5m^2
cost of white washing 376.5 m^2= 376.5*5
=₹1882.5