Question

that is the slope of a line perpendicular to the line joining A(5,1) and P where P 18
the mid-point of the segment joining (4,2) and (-6,4).
21. + the citzen pointer
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Answer 1

Answer:

3

Step-by-step explanation:

GT

A(5,1)

R(4,2)

S(-6,4)

P=(4-6/2,2+4/2)

=(-2/2,6/2)

=(-1,3)

A(5,1);P(-1,3)

Slope of AP=3-1/-1-5

=2/-6

=-1/3

Slope of the line perpendicular to AP is 3

HOPE THIS HELPS ........