Question

That is the value of sine in
right angle triangle, if Coast 4/5
​

Answer 1

Step-by-step explanation:

Cos●=4/5

sin●=under root5^2-4^2/5

=3/5

Answer 2

if cos is 4/5

Step-by-step explanation:

AB/AC =4/5., AB/4=AC/5 AB/4=K,AC/5=K. ,AB=4K,AC=5K using Pythagoras theorem,. AC2=AB2+BC2. (5K)2=(4K)2+(BC)2. 16K2+(BC)2=25K2,BC2=9K2,BC=√9K2,BC=3K ,Sin=3K/5K,Sin=3/5