Question

that sin theta minus cos theta upon sin theta + cos theta + sin theta + cos theta upon sin theta minus cos theta is equal to 2 upon 1 - 2 cos squared theta​

Answer 1

Step-by-step explanation:

= (SinO-CosO)/(SinO+CosO) + (SinO+CosO)/(SinO-CosO)

= (SinO-CosO)²+(SinO+CosO)²/(Sin²O-Cos²O)

= 1-2SinOCosO+1+2SinOCosO/(1-Cos²O-Cos²O)

= 2/(1-2Cos²O)