Question

that the area of a rhombus is equal to half of the product of the diagonals.
TRIANGLES ON THE SAME BASE AND BETWEEN THE SAME​

Answer 1

Answer:

in a rhombus <aob=<boc=<cod=<aoc

ar(rhombus) =1/2 abd ----(1)

ar( rhombus ) = 1/2 bcd---(2)

by combining both equations we get

ar(rhombus) = abcd

extra knowldge

ar( rhombus) = 1/2 × d1× d2