दविद्यात् समीकरण 3x²+√8x-16=0
के लिए अचर C का मान क्या है
Answers
Answer:
STEP
1
:
Equation at the end of step 1
(3x2 - 8x) - 16 = 0
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 3x2-8x-16
The first term is, 3x2 its coefficient is 3 .
The middle term is, -8x its coefficient is -8 .
The last term, "the constant", is -16
Step-1 : Multiply the coefficient of the first term by the constant 3 • -16 = -48
Step-2 : Find two factors of -48 whose sum equals the coefficient of the middle term, which is -8 .
-48 + 1 = -47
-24 + 2 = -22
-16 + 3 = -13
-12 + 4 = -8 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and 4
3x2 - 12x + 4x - 16
Step-4 : Add up the first 2 terms, pulling out like factors :
3x • (x-4)
Add up the last 2 terms, pulling out common factors :
4 • (x-4)
Step-5 : Add up the four terms of step 4 :
(3x+4) • (x-4)
Which is the desired factorization
Equation at the end of step
2
:
(x - 4) • (3x + 4) = 0
STEP
3
:
Theory - Roots of a product
3.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Step-by-step explanation:
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Step-by-step explanation:
by shridhara charya formula
