Question

दविद्यात् समीकरण 3x²+√8x-16=0
के लिए अचर C का मान क्या है
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Answer 1

Answer:

STEP

1

:

Equation at the end of step 1

(3x2 - 8x) - 16 = 0

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 3x2-8x-16

The first term is, 3x2 its coefficient is 3 .

The middle term is, -8x its coefficient is -8 .

The last term, "the constant", is -16

Step-1 : Multiply the coefficient of the first term by the constant 3 • -16 = -48

Step-2 : Find two factors of -48 whose sum equals the coefficient of the middle term, which is -8 .

-48 + 1 = -47

-24 + 2 = -22

-16 + 3 = -13

-12 + 4 = -8 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and 4

3x2 - 12x + 4x - 16

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (x-4)

Add up the last 2 terms, pulling out common factors :

4 • (x-4)

Step-5 : Add up the four terms of step 4 :

(3x+4) • (x-4)

Which is the desired factorization

Equation at the end of step

2

:

(x - 4) • (3x + 4) = 0

STEP

3

:

Theory - Roots of a product

3.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

by shridhara charya formula