Thd sum of a two digit number and the number obtained by reversing the order of the digits is 99.Find the number if the digits differ by 3
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sorry I don't know
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Answer:
Step-by-step explanation:
y=x-3
let the number be 10x+y
10x+y+10y+x=99
11x+11y=99
11(x+y)=99
x+y=9
x-y=3
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2x=12
x=6
y=3
the number is 10*6+3=60+3=63
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