the 0.2 grams of anhydrous organic acid on combustion 0.04 grams of water and 0.195 grams of Co2 the acid is diabetic acid and 0.5 grams of silver Sal leaves on ignition on 0.35 grams of silver the percentage of carbon and hydrogen in the compound is
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The molecular formula of the compound is (COOH)2
Explanation:
- Number of moles of Ag = 0.355 / 108
- Number of moles of (RCOO)2- = 0.355 / 216
- Molecular weight of (RCOO)2- = 0.145 / (0.355/ 216) = 88 + 2 = 90
- Number of moles of anhydrous organic acid = 0.2 / 90 = 0.00222 moles
- Number of moles of hydrogen = 0.04 x 2 / 18 = 0.004444 moles
- Number of carbon moles = 0.195 / 44 = 0.00444 moles
- Thus in 1 mole of acid we get 2 moles of hydrogen and 2 moles of carbon.
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