The 1 mol of an Ideal das A with 300 mm of Hg separated by 2 mol of another ideal gas B with 300 mm of Hg in a closed container at the same temperature. If the separator is removed then total pressure is
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Given-
P₁=P₂
n₁=1 mol
n₂=2 mol
P₁V₁=n₁RT ; P₂V₂=n₂RT
V₁=n₁RT/P₁ ; V₂=n₂RT/P₂
P=P₁V₁+P₂V₂/V₁+V₂
P= n₁RT+n₂RT / [n₁RT/P₁] + [n₂RT/P₂]
P=n₁RT+n₂RT/ [n₁RT+n₂RT] /P₁
P=P₁
If separtors removed then total pressure is 300mm of Hg.
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