Question

the 10 digit of a two digit number exceeds the unit digits but 5 . if the digits are reversed the new number is less by 45 if the sum of their digits is 9 find the number. find it with one variable​

Answer 1

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Answer 2

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the 10 digit of a two digit number exceeds the unit digits but 5 . if the digits are reversed the new number is less by 45 if the sum of their digits is 9 find the number. find it with one variable

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let the no. be 10x+y

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• x+y = 9-----------(i)
• (10x+y)-(10y+x)=45---------(ii)

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• the correct no.

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• solving eq (i)

(10x+y)-(10y+x) = 45

10x + y - 10y - x = 45

10x -x -10y+y = 45

9x - 9y = 45

9(x-y) = 45

x-y = 45/9

x-y = 5------------(iii)

• adding eq (i) and (iii)

x+y + x - y = 5+9

2x=14

x=14/2

x = 7

• putting value of x in eq (i)

x+y = 9

7+y = 9

y = 9-7

y=2

${\bold{\blue{\boxed{\bf{Answer}}}}}$

10x+y

10*7+2

70+2

72

Required number = 72

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