Question

the 10 term from the end in the A.P 5,8,11,........is 95 then the number of term in the A.P and the last term are

Answer 1

HEYA!

GOOD EVE & HERE'S YOUR ANSWER:

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tn= a+(n-1)d

a= 5 ,d=8-5=3,

t10=5+(10-1).3

t95= 5+9.3

t95=5+27

t95= 32

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Answer 2

The number of terms in the A.P is 40 and the last term is 122.

Step-by-step explanation:

The given AP is

5,8,11,.......

First term = 5

Common difference = 8-5 = 3

The nth term of an AP from end is

$b_n=l-(n-1)d$

where, l is last term of the AP and d is common difference.

10 term from the end in the A.P is 95.

$b_{10}=l-(10-1)3$

$95=l-(9)3$

$95=l-27$

$95+27=l$

$122=l$

Therefore, the last term is 122.

nth term of an AP is

$a_n=a+(n-1)d$

$122=5+(n-1)3$

$122=5+3n-3$

$122=2+3n$

$120=3n$

$40=n$

Therefore, the number of terms in the A.P is 40.

#Learn more

Find the 10th term from the end of A.P -15,-13,-11.......33

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