Question

the 10 term of AP:5,8,11,14......is ​

Answer 1

Answer:

first term + 9 *difference of terms

5+(9*3)

5+27=32

Answer 2

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GIVEN :

The A.P is 5,8,11,14,......

From this ,

The first term, a = 5

The common difference , d = t2 - t1

d = 8 - 5

d = 3

TO FIND :

The 10th term,t10 = ?

SOLUTION:

The general term,tn

$tn = a + (n - 1)d$

where n is the nth term.

t10 = a + ( 10 - 1 ) d

= a + 9 d

= 5 + 9(3)

= 5 + 27

t10 = 32

ANSWER : 32

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