Question

The 10 th term of an ap 5 ,9,13............is

Answer 1

a = 5

d = t2 - t1 = t3 - t2

= 9 - 5 = 13 - 9

= 4 = 4

so, d = 4

now,

an = a + ( n -1) d

a10 = 5 + (10 - 1) 4

= 5 + 9 ×4

= 5 + 36

= 41...

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Answer 2

Clearly on adding 4 to 5 we get 9, the 2nd term

So to get 10th term, Add 4 nine times to 4

=5+4*9

=5+36

=41

Step-by-step explanation:

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