Question

The 10 th term of the A. P: 13, 8, 3, - 2 ...
is​

Answer 1

Answer:

-32

Step-by-step explanation:

a = first term = 13

d = common difference = 8 - 13 => -5

nth term = a + (n - 1)d

Thus, 10th term = a + (10 - 1)d => a + 9d

=> 13 + 9(-5)

=> 13 - 45 => -32

Answer 2

Step-by-step explanation:

$first \: of \: all \: we \: find \: d \\ d = a2 - a1 \\ d = 8 - 13 \\ d = - 5 \\ \\ put \: the \: value \: of \: d \: in \: formula \: \\a10 = a + (n - 1)d \\ a10 = 13 + (10 - 1) \times - 5 \\ a10 = 13 + 9 \times - 5 \\ a10 = 13 - 45 \\ a10 = - 32$

I hope it helps you...........