Question

the 10 that term from end of the A. P -5,--10,-15.......,-1000is​

Answer 1

Answer:

Explanation:

a= -5,  d= -5  and an = -1000

an= a+ (n-1)d

= -1000 = -5+(n-1)(-5)

= -995/ -5 = (n-1)

=199+1 = n therefore, number of terms =n= 200

10th term from the end = 191st from the beginning

therefore,

a191= -5 + (191-1)(-5)

a191 = -5-950

therefore 10th term from end= 191st term from beginning= -955

hope this helped