the 10 that term from end of the A. P -5,--10,-15.......,-1000is
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Answer:
Explanation:
a= -5, d= -5 and an = -1000
an= a+ (n-1)d
= -1000 = -5+(n-1)(-5)
= -995/ -5 = (n-1)
=199+1 = n therefore, number of terms =n= 200
10th term from the end = 191st from the beginning
therefore,
a191= -5 + (191-1)(-5)
a191 = -5-950
therefore 10th term from end= 191st term from beginning= -955
hope this helped
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