The 104th term and 4th term of an A.P. are 125 and 0. Find the sum of first 35 terms
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given a 104= 125
a4=0
now.
to find- S35.
a + 103d=125
a+3d = 0
subtracting we get.
100d =125
d=125/100=5/4
now. d=5/4
a= -15/4..
S35= 35/2(2×-15/4 +34×5/4)
=35/2(-15/2+85/2)
= 35/2×35
=1225/2=612.5
therefore sum of first 35 terms is 612.5
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