the 10th and 18th term of an AP are 41 and 73 respectively find the 27th term?
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we are given
a+9d=41
a+17d=73
Substracting both
d=4
Putting in first one
a=5
now
t27=a+26d
=5+104
=109
a+9d=41
a+17d=73
Substracting both
d=4
Putting in first one
a=5
now
t27=a+26d
=5+104
=109
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