The 10th and 18th terms of an A.P. are 41 and 73 respectively. Find the 27th term.
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Answer:
The 27th term is 109
Step-by-step explanation:
Let , 1st term = a
common difference = d
nth term is a(n) = a + (n-1)d
according to question ,
a(10) = a + 9d = 41 → (1)
a(18) = a + 17d = 73 → (2)
(2) - (1) ⇒ 8d = 32
⇒ d = 4
∴ a = 5
hence 27th term is a(27) = 5 + 26×4 = 109
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