Question

the 10th and 18th terms of an A.P are 41 and 73 respectively. find 26th terms​

Answer 1

Answer:

Ans is 50

Step-by-step explanation:

Ans is 50

Hope it is correct

Answer 2

Let the first term be a and common difference be d then

T10 = a+(n-1)d

=>41 = a+ 9d equation( i )

T18 = a+(n-1)d

= >73= a+ 17dn equation(ii)

⇒ a+ 9d+ 8d= 73

⇒ 41+ 8d= 73

⇒ 8d= 73− 41

⇒ 8d= 32⇒ d= 4.

∴ a+ 9d= 41

⇒ a+ 9× 4= 41

⇒ a= 5

First term (a) = 5

common difference (d) = 4

Hence,

The 26th term

= a+(n-1)d

= 5 + 25 × 4

= 105