the 10th and 4th term of an A.P are 125 and find the sum of first 35 terms??
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Answer:
Step-by-step explanation:
a10 = 125
a+9d =125
a =125-9d .................(1)
a4 = 0
a+3d =0
a = -3d .................(2)
from 1 and 2
125-9d = -3d
-9d+3d = -125
-6d =-125
d =125/6
puttting d value in 2
a=-3(125/6)
a=-125/2
S35 = 35/2[2(-125/2)+34(125/6)]
you can do the remaining calculation and find it
Answered by
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Answer:Step-by-step explanation:a10 = 125a+9d =125a =125-9d .................(1) a4 = 0a+3d =0 a = -3d .................(2) from 1 and 2125-9d = -3d-9d+3d
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