Question

The 10th form of an AP is 25 and 18th term is 41. find the
14th term of this AP.​

Answer 1

Step-by-step explanation:

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SHAVANSH

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Answer 2

answer : 33

Step-by-step explanation:

an = a + n-1 *d

25 = a + 9 d and 41= a + 17d

now

a + 9d = 25

a + 17d = 41

changing signs we get

a + 9d =. 25

- a - 17d = -41

which is equal to

-8 d = - 16

therefore ...d = -16 / -8 = 2

now an = a + n-1 * d

25 = a + 9d

25 = a + 18

25 - 18 = a

7 = a

therefore 14th term =

14a = 7 + 13*2

= 7 + 26

ans = 33

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