the 10th term and 18th term and AP are 11 and 73 find the 26th term
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a(10) = a + 9d = 11
a(18) = a + 17d = 73
a(18) - a(10) = a + 17d - a - 9d = 73 - 11
=>8d = 62
=>d = 62/8 = 7.75
• a = 11 - 9d
=>11 - 69.75 = a
=>( -58.75)
a(26) = a + 25d = -58.75 + 193.75 = 135
a(18) = a + 17d = 73
a(18) - a(10) = a + 17d - a - 9d = 73 - 11
=>8d = 62
=>d = 62/8 = 7.75
• a = 11 - 9d
=>11 - 69.75 = a
=>( -58.75)
a(26) = a + 25d = -58.75 + 193.75 = 135
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