Question

the 10th term from the end of an ap - 5, - 10, - 15,............,-1000 is...​

Answer 1

Answer:

-50

Step-by-step explanation:

a10=a+(n-1)d

a10=a+(10-1)*-5

a10=-5-9*5

a10=-5-45

a10=-45

Answer 2

Answer:

Therefore the 10th term from the last is -950 i.e. $t_{190}=-950$

Step-by-step explanation:

First we need to find the no. of terms $n$

In this A.P $a=-5, d=t_2-t_1=-10-(-5)=-10+5=-5, n=?$

$n=\frac{l-a}{d}+1=\frac{-1000-(-5)}{-5}+1=\frac{-995}{-5}+1=199+1=200$

10th term from the end i.e. $t_{n-10}=t_{190}$

$t_n=a+(n-1)d\\\\t_190=-5+(190-1)\times-5=-950$

Therefore the 10th term from the last is -950 i.e. $t_{190}=-950$